# -*- noplot -*-
"""
matplotlib has support for FreeType fonts.  Here's a little example
using the 'table' command to build a font table that shows the glyphs
by character code.

Usage python font_table_ttf.py somefile.ttf
"""

import sys
import os

import matplotlib
from matplotlib.ft2font import FT2Font
from matplotlib.font_manager import FontProperties
import matplotlib.pyplot as plt

import six
from six import unichr

# the font table grid

labelc = ['0', '1', '2', '3', '4', '5', '6', '7', '8', '9',
          'A', 'B', 'C', 'D', 'E', 'F']
labelr = ['00', '10', '20', '30', '40', '50', '60', '70', '80', '90',
          'A0', 'B0', 'C0', 'D0', 'E0', 'F0']

if len(sys.argv) > 1:
    fontname = sys.argv[1]
else:
    fontname = os.path.join(matplotlib.get_data_path(),
                            'fonts', 'ttf', 'DejaVuSans.ttf')

font = FT2Font(fontname)
codes = list(font.get_charmap().items())
codes.sort()

# a 16,16 array of character strings
chars = [['' for c in range(16)] for r in range(16)]
colors = [[(0.95, 0.95, 0.95) for c in range(16)] for r in range(16)]

plt.figure(figsize=(8, 4), dpi=120)
for ccode, glyphind in codes:
    if ccode >= 256:
        continue
    r, c = divmod(ccode, 16)
    s = unichr(ccode)
    chars[r][c] = s

lightgrn = (0.5, 0.8, 0.5)
plt.title(fontname)
tab = plt.table(cellText=chars,
                rowLabels=labelr,
                colLabels=labelc,
                rowColours=[lightgrn]*16,
                colColours=[lightgrn]*16,
                cellColours=colors,
                cellLoc='center',
                loc='upper left')

for key, cell in tab.get_celld().items():
    row, col = key
    if row > 0 and col > 0:
        cell.set_text_props(fontproperties=FontProperties(fname=fontname))
plt.axis('off')
plt.show() 

• 2023/04/02 Ver=1.03 Python 3.11.2 で確認
• 2020/10/31 Ver=1.01 Python 3.7.8 で確認
• 2018/12/01 Ver=1.01 初版リリース

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